Question posted by Yvonne from Sri Lanka:
Question solved by Model Method: 900 people attended a party. 1/4 of the males and 1/7 of the females were children. the number of male and female adults were the same. how many women were there at the party?
Step 1: This question involves the Equal Concept. Since 1/4 of the males were children, then 3/4 of the males must be adults. We draw 3 boxes to represent the total number of male adults and 1 box to represent the total number of male children.
Step 2: Since 1/7 of the females were children, then 6/7 of the females must be adults. We were also given that the number of male and female adults were the same. Thus, 3/4 of the males(men) must be equal to 6/7 of females(women). So we draw 6 units of women to be equivalent to 3 big boxes representing all the men.
Step 3: Next, since each big box representing the males is equivalent to 2 small boxes representing the females, we divide each big box into 2 small boxes. We also add in 1 small box to represent 1/7 of the females (which are the female children).
Step 4: We then label 6 small boxes as "M" (men) and 2 small boxes as "C" (male children or boys). We also add in a bracket to the right to denote the total number of people (900) who attended the party.
From the model,
15 units ---------- 900 people
1 unit ---------- 900 people / 15 = 60 people
6 units ---------- 6 x 60 people = 360 people
Therefore, there were 360 women at the party.
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